SOLUTION: Story problem:
Johnny canoes down the American River with the current of 10km/hr in 6 hours. The return trip back up the River takes 15 hours. What is the rate of the canoe on the
Algebra ->
Expressions-with-variables
-> SOLUTION: Story problem:
Johnny canoes down the American River with the current of 10km/hr in 6 hours. The return trip back up the River takes 15 hours. What is the rate of the canoe on the
Log On
Question 208163: Story problem:
Johnny canoes down the American River with the current of 10km/hr in 6 hours. The return trip back up the River takes 15 hours. What is the rate of the canoe on the return trip?
You can put this solution on YOUR website! Johnny canoes down the American River with the current of 10km/hr in 6 hours.
The return trip back up the River takes 15 hours.
What is the rate of the canoe on the return trip?
:
let s = canoe speed in still water
then
(x+10) = his speed downstream
and
(x-10) = his speed upstream
:
The trip distance is the same downstream and upstream;
Write a distance equation, Dist = time * speed
;
up dist = down dist
15(s-10) = 6(s+10)
15s - 150 = 6s + 60
15s - 6s = 60 + 150
9s = 210
s =
s = 23 km/hr his speed in still water
then
23 - 10 = 13 km/hr on the return trip
:
:
You can check our solution by finding the actual dist:
6*33.333 = 200 mi
15*13.333 = 200 mi
