Question 208098: On a TV game show, the contestant is asked to select a
door and then is rewarded with the prize behind the door
selected. If the doors can be selected with equal probability,
what is the expected value of the selection if the
three doors have behind them a $40,000 foreign car, a $3
silly straw, and a $50 mathematics textbook?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! If the doors can be selected with equal probability,
what is the expected value of the selection if the
three doors have behind them a $40,000 foreign car, a $3
silly straw, and a $50 mathematics textbook?
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Random variable values are 40000, 3, and 50
The probability of each is 1/3
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Expected value = (1/3)(40000+3 + 50)
E(x) = (1/3)(40053) = $13,351.00
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Cheers,
Stan H.
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