SOLUTION: Hello! I have been working on this problem for the past 20 min P=13+45ln x represents the percentage of inbound email in the us that is considered spam, where x is the number of ye

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hello! I have been working on this problem for the past 20 min P=13+45ln x represents the percentage of inbound email in the us that is considered spam, where x is the number of ye      Log On


   

Question 208081: Hello! I have been working on this problem for the past 20 min P=13+45ln x represents the percentage of inbound email in the us that is considered spam, where x is the number of years after 2000. calculate to 6 decimals on each step when necessary.
Determine the percentage of spam in the year 2003. Round answer to 2 decimals.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Since "x is the number of years after 2000", this means that when the year is 2003, the value of x is x=3


So simply plug in x=3 into P=13%2B45%2Aln%28x%29 to get:


P=13%2B45%2Aln%283%29=13%2B45%2A1.0986=13%2B49.437=62.437


So when x=3, P=62.437. So the percentage of spam in 2003 is 62.437%