SOLUTION: determine whether each pair of equations represents parallel lines: y=-3x+1, 6x+2y=8

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Question 208010This question is from textbook elementary and intermediate algebra
: determine whether each pair of equations represents parallel lines:
y=-3x+1, 6x+2y=8
This question is from textbook elementary and intermediate algebra

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
determine whether each pair of equations represents parallel lines:
y=-3x+1, 6x+2y=8

There are several ways to do this. Pick whichever way
your teacher told you to use.

Method 1:  Put them both in slope-intercept form. If 
their slopes are equal, but they have different 
y-intercepts, then they are parallel.

Method 2:  Choose any two values for x.  Substitute 
           them both in each equation to find the 
           y-values corresponding to them.  If the 
           corresponding y-values have the same non-zero
           difference, then the lines are parallel.

Method 3:  Put them both in general form. Then 

system%28A%5B1%5Dx%2BB%5B1%5Dy=C%5B1%5D%2CA%5B2%5Dx%2BB%5B2%5D=C%5B2%5D%29

if A%5B1%5D%2FA%5B2%5D=B%5B1%5D%2FB%5B2%5D then they are parallel.   

----------------------

Method 1:  

system%28y=-3x%2B1%2C+6x%2B2y=8%29

The first one is already in the slope intercept form
y=mx%2Bb.  Get the second one in slope-intercept 
form, by solving for y

6x%2B2y=8

Add -6x to both sides:

2y=-6x%2B8

Divide every term by 2:

%282%2F2%29y+=%28%28-6%29%2F2%29x%2B%288%2F2%29

y=-3x%2B4

So the slope is the coefficient of x, which is -3
So the value of the slope m is the same in 
both equations, but their y-intercepts are different.
Therefore the lines those equations
represent are parallel.

----------------------------------

Method 2:

system%28y=-3x%2B1%2C+6x%2B2y=8%29

Substitite x=0 in each and solve for y:

In the first one:

y=-3x%2B1  
y=-3%280%29%2B1
y=1

In the second one:

6x%2B2y=8
6%280%29%2B2y=8
0%2B2y=8
2y=8
y=4

Subtract them, second y - first y = 4-1=3

Substitite x=1 in each and solve for y:

In the first one:

y=-3x%2B1  
y=-3%281%29%2B1
y=-3%2B1
y=-2

In the second one:

6x%2B2y=8
6%281%29%2B2y=8
6%2B2y=8
2y=2
y=1

Subtract them, second y - first y = 1-%28-2%29=1%2B2=3

We get the same difference 3, so the lines represented
by those equations are parallel.

------------------------------------------------

Method 3:

system%28y=-3x%2B1%2C+6x%2B2y=8%29

Get the forst one in general form:

y=-3x%2B1
3x%2By=1

So the system is now:

system%283x%2By=1%2C+6x%2B2y=8%29

See if the coefficients of x and y are in
the same proportion:

Is 3%2F6=1%2F2 true?

Yes it is, therefore the lines those equations
represent are parallel.

Edwin