SOLUTION: what is the description of formation in h(x)=-e^x? Is it reflected in the y-axis? or the x-axis? I'm so confused....

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Question 207963: what is the description of formation in h(x)=-e^x? Is it reflected in the y-axis? or the x-axis? I'm so confused....
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If we let f%28x%29=e%5Ex, then h%28x%29=-f%28x%29=-e%5Ex. Recall that f(x) is used in place of 'y'. So what does -f%28x%29 mean? It simply means -y. So what we're doing is taking EVERY y coordinate on the graph of e%5Ex and negating it to get a y-coordinate on -e%5Ex. Visually, we're reflecting the graph over the x-axis.


Here's the visual:

Graph of f%28x%29=e%5Ex





and the graph of h%28x%29=-e%5Ex



Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
what is the description of formation in h(x)=-e^x? Is it reflected in the y-axis? or the x-axis? I'm so confused....
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The basic function is y = e^x and it looks like this:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C2.71828%5Ex%29
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Your function is y = -e^x and it looks like this:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C-2.71828%5Ex%29
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Notice that e^x has flipped over the y-axis.
That means it was reflected in the y-axis.
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Cheers,
Stan H.