Question 207935This question is from textbook College Math 1
: Given a point (5,-5) on the terminal side of angle0, find the value of sin.
This question is from textbook College Math 1
Found 2 solutions by HyperBrain, ikleyn:
Answer by HyperBrain(694)   (Show Source):
You can put this solution on YOUR website! Let x=angle
---
Since the terminal side contains the point (5,-5), the terminal side has slope -5/5=-1 and so
tan x=-1
x=135 or 315 degrees
Since (5,-5) is at quad. II, then x=135 degrees.
---
So,
sin x=sin 135=sin 45=
Answer by ikleyn(53937)  (Show Source):
You can put this solution on YOUR website! .
This question is from textbook College Math 1
Given a point (5,-5) on the terminal side of angle0, find the value of sin.
~~~~~~~~~~~~~~~~~~~~~~~~~~
The answer in the post by @HyperBrain " sin(x) = sin(135) = sin(45) = " is INCORRECT.
The correct answer is " sin(x) = sin(315) =  ".
The general error by @hHyperBrain is that he thinks that the angle is in QII, while in reality it is in QVI.
So far, I checked about 30 solutions by @HyperBrain, and found that 7 of them are solved incorrectly.
It is very sad to see so low level tutors at this forum.
In reality, it is not an allowed level for a tutor - it is a level of average student, whose typical score in Math is 3 of 5.
His goal should be to learn for himself - not to deceive other people by presenting himself as a tutor.
|
|
|
