SOLUTION: If a ball is thrown upwards at 40 feet per second from a rooftop 24 feet above the ground, then its height above the ground t seconds after it is thrown is given by h = - 16 t2 + 4

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Question 207888: If a ball is thrown upwards at 40 feet per second from a rooftop 24 feet above the ground, then its height above the ground t seconds after it is thrown is given by h = - 16 t2 + 40 t + 24.
a. Rewrite the above formula with the polynomial on the right hand side factored completely.
b. Use the factored version of the formula to find h when t = 3.

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
h+=+-+16+t%5E2+%2B+40+t+%2B+24
h+=+-8%2A%282t%5E2+-+5t+-+3%29
h+=+-8%2A%282t%2B1%29%28t-3%29
You can see that at t=3, the term (t-3) above would evaluate to 0.
Since 0* anything = 0, then h(3) = 0.