SOLUTION: A rectangular deck has an area of (x2 + 6x + 8) square feet. If its width is (x + 2) feet then: a. Find its length in terms of ‘x’. b. If x = 3, what will be the area, length

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Question 207887: A rectangular deck has an area of (x2 + 6x + 8) square feet. If its width is (x + 2) feet then:
a. Find its length in terms of ‘x’.
b. If x = 3, what will be the area, length and width in feet.

Found 2 solutions by vleith, rapaljer:
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Area = (x^2 + 6x + 8)
Width = (x +2)
Area = Length * Width
Area/Width = Length
%28x%5E2+%2B+6x+%2B+8%29%2F%28x%2B2%29+=+Length
%28%28x%2B2%29%28x%2B4%29%29%2F%28x%2B2%29+=+Length
x%2B4+=+Length
If x=3 what are the area, length and width
Width = (x+2) = 3+2 = 5
Length = (x+4) = (3+4) = 7
Area = x^2 +6x + 8 = 3^2 + 6*3 + 8 = 9 + 18 + 8 = 35
Area = Length*Widht = 7 * 5 = 35

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + 6x +8 just happens to factor into (x+2)(x+4)

So, if x+2 is the width, then x+4 must be the length.

If x=3, then the width is x+2, which is 5 feet, the length is x+4, which is 7 feet, and the area is the product 5*7 which is 35 square feet.

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