SOLUTION: A rectangular pool is 14 metres long and 6 metres wide. It is surrounded by a pebble path of uniform width {{{x}}} metres. If the area of the path is {{{96m^2}}}, find the width.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A rectangular pool is 14 metres long and 6 metres wide. It is surrounded by a pebble path of uniform width {{{x}}} metres. If the area of the path is {{{96m^2}}}, find the width.       Log On


   



Question 207877: A rectangular pool is 14 metres long and 6 metres wide. It is surrounded by a pebble path of uniform width x metres. If the area of the path is 96m%5E2, find the width.
Answer by pjalgeb(9) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
Length of Pool = 14 metres
Width of Pool = 6 metres
Area of Path = 96m%5E2

Required:
x = Width of Path = ?

Solution:
Area of Pool = L x W
= 14m x 6m
= 84+m%5E2

Area of Path = 96m%5E2

Total Area = Area of Pool + Area of Path
= 84m%5E2 + 96m%5E2
= 160m%5E2

Because the pebble path is of uniform width, then the equation for total area is:

(Length of Pool+Width of Path)* (Width of Pool +Width of Path) = Total Area
or
%282x+%2B14%29%2A%282x+%2B+6%29+=+160 --> We use 2x because the path is on both sides
4x%5E2+%2B+28x+%2B+12x+%2B+84+=+160 --> Distributive Property
4x%5E2+%2B+40x+%2B+84+=+160 --> Combine Like Terms

%284x%5E2+%2B+40x+%2B+84%29%2F4+=+160%2F4 --> Divide both sides by 4
x%5E2+%2B+10x+%2B+21+=+40 --> The result is a quadratic equation

x%5E2+%2B+10x+%2B+21+-+21+=+40-21 --> Subtract 21 from both sides

x%5E2+%2B+10x+=+19 --> The resulting equation can be solved by method of completing the square

x%5E2+%2B+10x+%2B+25=+19+%2B+25+ -->Add 25 to both sides to complete the square

x%5E2+%2B+10x+%2B+25=+44+ -->The left side is now a perfect square trinomial


%28x+%2B+5%29%5E2=+44+ -->Factor the left side to a perfect binomial square

sqrt%28%28x+%2B+5%29%5E2%29=+sqrt%2844%29+ -->We can now solve for X by finding the square root of both sides

+x%2B5+=+%2B-+sqrt%2844%29+ --> Even radicals have two roots(+ and -)


+x%2B5+=+%2B-+sqrt%284%2A11%29%29+ -->Factor the Radicand into 4 and 11

+x%2B5+=+%2B-+2sqrt%2811%29%29+ --> The square root of 4 is 2, so this can be moved out of the radical

+x=+-5+%2B-+2sqrt%2811%29%29+ --> There is no such thing as negative length so we use the other answer.
+x=+-5+%2B+2sqrt%2811%29%29+ --> This is the simplified answer

or by using calculator we get: x+=+1.633


Lets check our answer:
(2x+14)(2x+6) = 160 --> From the equation for the total area
[2(1.633) + 14][2(1.633) +6] = 160 --> Substitute the value of x with our answer 1.633
(17.266)(9.266) = 160
160 = 160

Answer:
The width of the path is 1.633 metres.