Question 207833: log(5)^(x)-log(5)^(x-20)=1
log(2)^(x)+5=8-log(2)^(x+7)
I need help with finding the answer and the steps to getting the answer. Answer by dlam5(15) (Show Source):
You can put this solution on YOUR website! For
Take log(5)^x; by logarithm properties, take the x out of the exponent, which is...
x log(5) ;
Now, take log(5)^(x-20); and do the same DISTRIBUTIVE property of log by taking...
(x-20) log 5; now distribute the log 5 for x and 20; this then cleans up to be...
xlog5 - 20log5.
Your equation should come out to be xlog5 - xlog5 -20log5 =1.
But, look closely; XLOG5 - XLOG5= 0; so x doesn;t have an answer as a variable.
Therfore, this equation is the EMPTY SET (undefined).
Try the next one in the same manner, and e-mail me if you need any help.
Thanks,
dlam5 :)
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