Question 207741: The perimeter of a rectangle is 38 m. The length is four more than two times the width. What is the width?
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Let x = width of the rectangle
2x+4= length of the rectangle
2W + 2L = P
2(x) + 2(2x+4) = 38
2x + 4x +8 = 30
6x + 8= 38
6x=30
x=5 Width
2x+4 = Length
2*5+4 = Length
10+4 = 14 Length
Check: 2*5 + 2 * 14 = 10 + 28 = 38 Perimeter
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R^2
Dr. Robert J. Rapalje
Seminole State College
Altamonte Springs Campus
Florida
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