Question 207730: A parallelogram has the points A(1, -1), B(7,3), C (3,5), D(-3,0). AB is just an interval.Give the equation of the line that AB lies on :( dont get it
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! A(1,-1),,,,,and,,,,B(7,3),,,,,,define a line... What is eqn of line
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Remember ,,,,y=mx+b,,,,and m=(y2-y1)/x2-x1)
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m=(3-(-1))/(7-1)=4/6=+2/3
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y=mx+b,,,,y=(2/3)x +b,,,and now substitute (1,-1)
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-1 = (2/3)(1) +b,,,,,b= -1 2/3
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finally y= (2/3)x - 1 2/3
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Converting this to standard form(ax +by=c),,,,,lets multiply by 3
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3y =2x-5,,,,or 3y -2x = -5,,,or 2x-3y=5
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checking(1,-1),,,,2(1) -3(-1) = 5,,,,ok
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(7,3),,,,2(7)-3(3)=5,,,,,ok
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