SOLUTION: Can you please help me solve this problem: 4e^2x=12. What I've done so far is add natural log to both sides. ln^4e*2x= ln12. After this I am not sure what to do next.
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-> SOLUTION: Can you please help me solve this problem: 4e^2x=12. What I've done so far is add natural log to both sides. ln^4e*2x= ln12. After this I am not sure what to do next.
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Question 207687: Can you please help me solve this problem: 4e^2x=12. What I've done so far is add natural log to both sides. ln^4e*2x= ln12. After this I am not sure what to do next. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Can you please help me solve this problem: 4e^2x=12. What I've done so far is add natural log to both sides. ln^4e*2x= ln12. After this I am not sure what to do
next.
:
Do this first: = 12
Divide both sides by 4: = = 3
then
2x*ln(e) = ln(3)
:
The natural log of e is one so it's just
2x = ln(3)
:
2x = 1.0986
x =
x = .5493
:
:
Check solution on a good calc: enter: 4*e^(2*.5493) should get 11.9998 ~ 12
