SOLUTION: Factor Difference of Cubes 64y^3-8

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Question 207569This question is from textbook beginning algebra
: Factor Difference of Cubes
64y^3-8 This question is from textbook beginning algebra

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
64y^3-8
= 8*(8y^3 - 1)
= 8*(2y-1)*(4y^2 + 2y + 1)
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Any difference of cubes is like that.
a^3 - b^3 = (a-b)*(a^2 + ab + b^2)
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Any difference of odd powers is similar
a^5 - b^5 = (a-b)*(a^4 + a^3b + a^2b^2 + ab^3 + b^4)