SOLUTION: one number is two less than a second number. if you take one-half of the first number and increase it by the second number, the result is at least 41. find the least possible value
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Question 207562: one number is two less than a second number. if you take one-half of the first number and increase it by the second number, the result is at least 41. find the least possible value for the second number. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! one number is two less than a second number. if you take one-half of the first number and increase it by the second number, the result is at least 41. find the least possible value for the second number.
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Let 1st be "a" ; 2nd be "b"; 3rd be "c"
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Equations:
a = b-2
(1/2)a+b >=41
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Substitute a = b-2 into the 2nd equation and solve for "b":
(1/2)(b-2)+b >= 41
Multiply thru by 2 to get:
(b-2)+2b >= 82
3b >= 84
b >= 28
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Cheers,
Stan H.
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