SOLUTION: Solve for x where x is a real number, sin 2x = sin x, 0 less than or equal to x less than or equal to 2 pi

Algebra ->  Trigonometry-basics -> SOLUTION: Solve for x where x is a real number, sin 2x = sin x, 0 less than or equal to x less than or equal to 2 pi      Log On


   



Question 207537: Solve for x where x is a real number,
sin 2x = sin x, 0 less than or equal to x less than or equal to 2 pi

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x where x is a real number,
sin 2x = sin x, 0 less than or equal to x less than or equal to 2 pi
------------------------------
2sinxcosx = sinx
Factor:
sinx(2cosx-1) = 0
sinx = 0 or 2cosx-1 = 0
sinx = 0 or cosx = 1/2
x = 0 or pi OR x = pi/3 or (5/3)pi
========================================
Cheers,
Stan H.