Question 207398This question is from textbook Elementary and Intermediate Algebra
: The members of a flying club plan to share equally the cost of a $200,000 airplane. The members want to find 5 more people to join the club so that the cost per person will decrease by $2000. How many members are currently in the club?
I don't know if I did it right. I did not use any formula. I took 2000/5 = 400, then I took 200,000/400 = 500. So, I got 500 current club members. Will you please check this? Thank you!!
This question is from textbook Elementary and Intermediate Algebra
Found 2 solutions by jim_thompson5910, MathTherapy: Answer by jim_thompson5910(35256) (Show Source): Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!
Let the current amount of members be M
Since the cost of the plane is $200,000, then the current cost, per
person is:
Since they wish to get 5 more members, then the new amount of members then would be:
M + 5
Therefore, the new cost, then, per person would be:
Now, since the cost per person would decrease by $2,000 when 5 new members are admitted, then we get:
200,000(M + 5) - 200,000(M) = 2,000(M)(M + 5) ------> Multiplying entire equation by LCD, M(M + 5)
(M + 25)(M - 20) = 0
M = - 25, or 20
Ignore M = - 25, so M = 20
Therefore, the current amount of members in the club is , but will change to 25 (20 + 5) after 5 new ones are admitted.
------------
Check
------------
Current amount of members: 20. Cost per person = = $10,000.
New amount of members after 5 new ones are admitted: 25 (20 + 5). New cost per person then would be: = $8,000.
Reduction in price per person then would be $2,000 ($10,000 - $8,000)
|
|
|