SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 mph and train B is traveling at 70 mph. Train A passesa station at 12:20 P.M. If t
Question 207379: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 mph and train B is traveling at 70 mph. Train A passesa station at 12:20 P.M. If train B passes the same station at 12:32 P.M., at what time will train B catch up to train A?" Found 2 solutions by ankor@dixie-net.com, Alan3354:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Trains A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 60 mph and train B is traveling at 70 mph.
Train A passes a station at 12:20 P.M.
If train B passes the same station at 12:32 P.M.
, at what time will train B catch up to train A?"
:
from the given information, we know that train B is 12 min (.2 hr) behind
train A, when train A passes the station
:
The distance between the trains at this time: .2 * 70 = 14 mi
:
Let t = time required for train B to catch train a
:
write a distance equation: Dist = speed * time
:
Train B travel dist = Train A travel dist + 24 mi
70t = 60t + 14
70t - 60t = 14
10t = 14
t =
t = 1.4 hr or 1 hr 24 min (.4*60=24)
:
12:20 + 1:24 = 1:44 pm, B catches A
You can put this solution on YOUR website! Trains A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 60 mph and train B is traveling at 70 mph.
Train A passes a station at 12:20 P.M.
If train B passes the same station at 12:32 P.M.
, at what time will train B catch up to train A?"
-------------
Train A is 12 miles ahead when Train B passes the station (60 mph x 0.2 hours).
Train B is gaining at 10 mph (70-60).
12 miles/10 mph = 1.2 hours or 1 hr 12 minutes
12:32 + 1:12 = 1344 (or 1:44 P.M.)
