SOLUTION: I'm about to go crazy over here trying to figure out this problem!!! Can you PLEASE tell me the value of M in the equation; log{{{6}}}(3m+7) - log{{{6}}}(m+4) = 2log{{{6}}}6 - 3log
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-> SOLUTION: I'm about to go crazy over here trying to figure out this problem!!! Can you PLEASE tell me the value of M in the equation; log{{{6}}}(3m+7) - log{{{6}}}(m+4) = 2log{{{6}}}6 - 3log
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Question 20723: I'm about to go crazy over here trying to figure out this problem!!! Can you PLEASE tell me the value of M in the equation; log(3m+7) - log(m+4) = 2log6 - 3log3. I tried to solve it, but I got stuck. I got as far as log(3m+7) - log(m+4) = log36 - log27. PLEASE HELP ME!!! Answer by askmemath(368) (Show Source):
You can put this solution on YOUR website! Did you know that logm - log b can be re-written as
log
So you now get log = log
Since both sides are to the same log, the log can be removed thus leaving you with
=
Can you solve it from here?
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