SOLUTION: write a linear equation that goes through the point(3,-8) and has a slope of 1/2

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Question 207229: write a linear equation that goes through the point(3,-8) and has a slope of 1/2
Found 2 solutions by jim_thompson5910, checkley77:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

If you want to find the equation of line with a given a slope of 1%2F2 which goes through the point (3,-8), you can simply use the point-slope formula to find the equation:



---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point


So lets use the Point-Slope Formula to find the equation of the line


y--8=%281%2F2%29%28x-3%29 Plug in m=1%2F2, x%5B1%5D=3, and y%5B1%5D=-8 (these values are given)


y%2B8=%281%2F2%29%28x-3%29 Rewrite y--8 as y%2B8


y%2B8=%281%2F2%29x%2B%281%2F2%29%28-3%29 Distribute 1%2F2


y%2B8=%281%2F2%29x-3%2F2 Multiply 1%2F2 and -3 to get -3%2F2


y=%281%2F2%29x-3%2F2-8 Subtract 8 from both sides to isolate y


y=%281%2F2%29x-19%2F2 Combine like terms -3%2F2 and -8 to get -19%2F2


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Answer:


So the equation of the line with a slope of 1%2F2 which goes through the point (3,-8) is y=%281%2F2%29x-19%2F2

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Y=mX+b
-8=1/2*3+b
-8=1.5+b
b=-8-1.5
b=-9.5 y intercept
Thus this line equation is:
y=x/2-9.5
+graph%28+300%2C+200%2C+-6%2C+25%2C+-10%2C+10%2C+x%2F2+-9.5%29+ (graph 300x200 pixels, x from -6 to 25, y from -10 to 10, x/2 -9.5).