SOLUTION: Tickets at a football match cost $8, $15 or $20 each. The number of $15 tickets sold was double the number of $8 tickets sold. 6000 more $20 tickets were sold than $15 tickets. If
Algebra ->
Equations
-> SOLUTION: Tickets at a football match cost $8, $15 or $20 each. The number of $15 tickets sold was double the number of $8 tickets sold. 6000 more $20 tickets were sold than $15 tickets. If
Log On
Question 207096: Tickets at a football match cost $8, $15 or $20 each. The number of $15 tickets sold was double the number of $8 tickets sold. 6000 more $20 tickets were sold than $15 tickets. If the total gate receipts were $783000, how many of each type of ticket was sold? Answer by rfer(16322) (Show Source):
You can put this solution on YOUR website! x=8500
$8*x=$68000
$15*2x=$255000
$20*2x+6000=$460000
-------------------
8x+15(2x)+20(2x+6000)=783000
8x+30x+40x+120000=783000
78x=663000
x=8500
(