SOLUTION: A truck can be rented from Basic Rental for $50 per day plus $0.20 per mile. Roadrunners charges $20 per day plus $0.50 per mile to rent the same truck. How many miles must be driv

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: A truck can be rented from Basic Rental for $50 per day plus $0.20 per mile. Roadrunners charges $20 per day plus $0.50 per mile to rent the same truck. How many miles must be driv      Log On


   



Question 206985: A truck can be rented from Basic Rental for $50 per day plus $0.20 per mile. Roadrunners charges $20 per day plus $0.50 per mile to rent the same truck. How many miles must be driven in a day to make the rental cost for Basic Rental a better deal than that for Roadrunners?

Found 2 solutions by rfer, MathTherapy:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
50+.2x+20+.5x
-.3x=-30
.3x=30
x=100 mi
-------------
50+.2(100)=20+.5(100)
$70=$70

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Since Basic Rental charges $50, plus $0.20 per mile, and since Roadrunners

charges $20, plus $0.50, per mile, then in order for Basic Rental to have a

better rental deal than Roadrunners, we'll have:

50 + .2(m) < 20 + .5(m) (using m for amount of miles)

50 + .2m < 20 + .5m

-.3m < - 30

m+%3E+%28-30%29%2F%28-.3%29 ------> m > 100

Therefore, in order for Basic Rental to have a better deal than Roadrunners,
the renter has to rent for MORE THAN highlight_green%28100%29 miles

Check:
Since m > 100, we'll use value of 101

50 + .2(101) < 20 + .5(101)

50 + 20.20 < 20 + 50.50

70.20 < 70.50