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Question 206928This question is from textbook New Syllabus Mathematics D Book 4
: I donot know whether to put this question on this department or in the others. If you know where to submit the question please let me know. Anyways the question is the following;
Kindly, help me solve this question it is urgent!
I have never solved this type of question.
A wheel of radius 40cm is turning about a fixed axis through the centre of the wheel at acentre rate of 2 revolutions per minute. Calculate the
(a) Angle through which the wheel turns in 10 seconds.
(b) Distance moved by a point on the rim in 10 seconds.
I hope someone will solve it. I shall be highly obliged to you.
Thanks,
This question is from textbook New Syllabus Mathematics D Book 4
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A wheel of radius 40cm is turning about a fixed axis through the centre of the wheel at acentre rate of 2 revolutions per minute. Calculate the
(a) Angle through which the wheel turns in 10 seconds.
It turns 720º in 60 seconds (2 revolutions in 1 minute).
That's 12º per second.
12º/sec x 10 sec = 120º
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(b) Distance moved by a point on the rim in 10 seconds.
It moves 120º as determined above. That's 1/3 of a revolution.
The circumference is 40*2pi cm = 80pi
120º is 1/3 of that.
s = 80pi/3
s =~ 83.776 cm
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