SOLUTION: Train A and train B are traveling on parallel tracks, going in the same direction. Train A is going 60mph and train B is going 80mph. Train A passes a station at 5:15pm. If train B

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Question 206759: Train A and train B are traveling on parallel tracks, going in the same direction. Train A is going 60mph and train B is going 80mph. Train A passes a station at 5:15pm. If train B passes the same station as 5:27pm, what time will train B catch up to train A?
Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
Train A and train B are traveling on parallel tracks, going in the same direction. Train A is going 60mph and train B is going 80mph. Train A passes a station at 5:15pm. If train B passes the same station as 5:27pm, what time will train B catch up to train A?
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From 515 to 527 is 12 minutes = 0.2 hours.
Train A will be 60mph * 0.2 hour = 12 miles ahead when Train B passes the station.
Train B is gaining on train A at 20 mph (80-60).
12 miles/20 mph = 0.6 hours = 36 minutes
5:27 + 0:36 = 6:03

Answer by MathTherapy(10555) (Show Source):
You can put this solution on YOUR website!

Train A, after passing the station is hr or hr ahead of Train B

When Train B catches up to Train A, both trains will have traveled the same distance

Let the time that it takes Train B to catch Train A be T

Since the trains' distances will be equal when Train B catches up to Train A, then we'll have:

------> 60T + 12 = 80T

-20T = - 12

hr ------> hr ------> 36 minutes

Now, since it'll take Train B 36 minutes to catch Train A, then Train B will

catch Train A at :pm, which is 36 minutes after Train B passes the station at 5:27pm.