SOLUTION: A basket contains red and green candies. If one third of the green candies are removed, it is found that the number of red and green candies remaining in the basket is now the same

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A basket contains red and green candies. If one third of the green candies are removed, it is found that the number of red and green candies remaining in the basket is now the same      Log On


   

Question 206739: A basket contains red and green candies. If one third of the green candies are removed, it is found that the number of red and green candies remaining in the basket is now the same. What was the original percentage of red candies in the basket?
(A) 25 (B) 33 1/3 (C) 40 (D) 60 (E) None of these
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A basket contains red and green candies. If one third of the green candies are removed, it is found that the number of red and green candies remaining in the basket is now the same. What was the original percentage of red candies in the basket?
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red = (2/3)green
red/green = 2/3 = 0.6666667 = (66 2/3)%
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Cheers,
Stan H.
(A) 25 (B) 33 1/3 (C) 40 (D) 60 (E) None of these