SOLUTION: A class of 43 students is to be divided into committees so that each student serves on exactly one committee. Each committee must have at least 3 students and at most 5 students.

Algebra ->  Inequalities -> SOLUTION: A class of 43 students is to be divided into committees so that each student serves on exactly one committee. Each committee must have at least 3 students and at most 5 students.       Log On


   

Question 206563This question is from textbook Let's review integrated algebra
: A class of 43 students is to be divided into committees so that each student serves on exactly one committee. Each committee must have at least 3 students and at most 5 students. How do I determine which inequality would represent the possible number of committees, X, that could be formed? This question is from textbook Let's review integrated algebra

Answer by HyperBrain(694) About Me  (Show Source):
You can put this solution on YOUR website!
The number of ways to select 3 students from 43 is 43C3=43!/(3!40!)=12341.
the number of ways to select 5 students from 43 is 43C5=43!/(5!38!)=962598.
::
Therefore, 12341<=x<=962598
Power up,
HyperBrain!