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Question 206541: The equation, in general form, of the line that passes through the point (7,-7) and is perpendicular to the line 8x-6y+2=0 is , where A= B= C=
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The equation, in general form, of the line that passes through the point (7,-7) and is perpendicular to the line 8x-6y+2=0 is , where A= B= C=
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Find the slope of the given line:
6y = 8x+2
y = (4/3)x + (1/3)
The slope of the given line is 4/3
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Every line perpendicular to the given line must have
a slope of -3/4
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Find the intercept:
Since the form is y = mx+b, -7=(-3/4)*7+b
-7 = (-21/4)+b
(-28/4)+(21/4) = b
b = (-7/4)
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Equation:
y = (-3/4)x - (7/4)
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Cheers,
Stan H.
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