SOLUTION: Could you help me solve this algebraic expression? 6a+8b. a=4/5, b=3/5

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Question 206504: Could you help me solve this algebraic expression? 6a+8b. a=4/5, b=3/5
Found 2 solutions by jim_thompson5910, rfer:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
6a%2B8b Start with the given expression.


6%284%2F5%29%2B8%283%2F5%29 Plug in a=4%2F5 and b=3%2F5


%286%2A4%29%2F5%2B%288%2A3%29%2F5 Multiply the fractions


24%2F5%2B24%2F5 Multiply


%2824%2B24%29%2F5 Combine the fractions. This is possible since the fractions have equal denominators.


48%2F5 Add


So 6a%2B8b=48%2F5 when a=4%2F5 and b=3%2F5

Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
6a+8b
6(4/5)+8(3/5)
24/5+24/5=48/5=9 3/5
Remember that the 6 and the 8 are the same as 6/1 and 8/1
and you can multiply fractions directly without common denominators.
Then just add the fraction because 5 is your common denomintor for this addition.