SOLUTION: Solve the problem. Use 3.14 as an approximation for π where appropriate. At $ 2.70 per ft3, how much will it cost to fill an ice chest with dimensions of ? 8ft. x 7and 1/2

Algebra ->  Probability-and-statistics -> SOLUTION: Solve the problem. Use 3.14 as an approximation for π where appropriate. At $ 2.70 per ft3, how much will it cost to fill an ice chest with dimensions of ? 8ft. x 7and 1/2      Log On


   



Question 206400: Solve the problem. Use 3.14 as an approximation for π where appropriate.
At $ 2.70 per ft3, how much will it cost to fill an ice chest with dimensions of ?
8ft. x 7and 1/2ft. x 12ft.

This one has me confused on whether I am looking for the volume of what object?

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
You are looking for a volume. And it look sliek the volume of a 'cubic type' ice chest. Not sure where the value of pi (3.14) plays here.
VolumeOfChest+=+8+%2A+7.5+%2A+12
V+=+720 cubic feet
You are told ice costs 2.70/cubicfoot
So
Cost+=+Volume%2FCostPerUnit
Cost+=+720+%2F+2.70
Cost+=+267.67
That's a lot of ice