SOLUTION: hey.. thank you very much. The question is- m= (Mo) / sqrt( 1- v^2/ c^2 where mo= rest mass c= speed of light if Captian kirks rest mas is 80kg, how much would he weigh i

Algebra ->  Length-and-distance -> SOLUTION: hey.. thank you very much. The question is- m= (Mo) / sqrt( 1- v^2/ c^2 where mo= rest mass c= speed of light if Captian kirks rest mas is 80kg, how much would he weigh i      Log On


   

Question 206226: hey.. thank you very much. The question is-
m= (Mo) / sqrt( 1- v^2/ c^2 where
mo= rest mass
c= speed of light
if Captian kirks rest mas is 80kg, how much would he weigh if he was moving at
i)80% of speed of light ( c=3 x 10^8 m/s)
ii)90% of speed of light
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
1) I'll do the first one, you can do the second one
+m+=++%28+M%5Bo%5D+%2F+%28sqrt%281-+%28v%5E2%2Fc%5E2%29%29%29+%29
where m%5Bo%5D+=+80 and v=+0.8c
Substituting those values yields:
+m+=++%28+80+%2F+%28sqrt%281-+%28%280.8c%29%5E2%2Fc%5E2%29%29%29+%29
+m+=++%28+80+%2F+%28sqrt%281-+%280.64c%5E2%2Fc%5E2%29%29%29+%29
+m+=++%28+80+%2F+%28sqrt%281-+0.64%29+%29+%29
+m+=++%28+80+%2F+%28sqrt%280.36%29+%29+%29
+m+=++%28+80+%2F+%280.6%29+%29
m+=+133.33 kg
Now you use the same process, except this time the good Captain is moving at 0.9c.
You have the con!