SOLUTION: Here is my question:
1-logx = log(3x-1)
I started with:
1 - logx = log3x - log
1 = log4x - log
The answer is 2, but I don't know where to go from here!
Can anyone help?
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-> SOLUTION: Here is my question:
1-logx = log(3x-1)
I started with:
1 - logx = log3x - log
1 = log4x - log
The answer is 2, but I don't know where to go from here!
Can anyone help?
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Question 20619: Here is my question:
1-logx = log(3x-1)
I started with:
1 - logx = log3x - log
1 = log4x - log
The answer is 2, but I don't know where to go from here!
Can anyone help?
Thanks!
Sandy Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1-logx=log(3x-1)
1=logx+log(3x-1)
You have to know log(AB)=logA+logB
So, 1=log[x(3x-1)]
1=log[3x^2-x]
Assuming the base is 10 you get:
10^1=3x^2-x
3x^2-x-10=0
(3x+5)(x-2)=0
x cannot be negative so x=2
Cheers,
Stan H.
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