Question 206170: Problem #4. The Rhombuses (Parallelogram of all 4 sides equal ) OABC and ODEC of the equal length and width of 10 inches each and height of 7 inches each, are drawn inside a quarter of a circle of radius 18 inches as shown in the figure below.
(a) find the perimeter of each of the Rhombuses.
(b) Find the perimeter of the quarter-circle. (Use Pi= 3.14).
(c) Find the area of each of the Rhombuses.
(d) Find the area of the quarter circle OPQ. (Pi = 3.14).
(e) Find the area of the region inside the quarter-circle but outside the two Rhombuses.
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! (a) each rhombus has 4 sides of 10 each or perimeter of 40 inches
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(b)Per of qtr circle = 18 +18 +1/4 circumference
cir =2*pi*r=2*3.14*18 = 113.04,,,,,1/4 cir = 28.26
per of qtr circle = 18+18+28.26 = 64.26 inches
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(c)Each Rhombus has a base of 10 and a height of 7,,,a=Bh=(10)(7)=70 sq in
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(d)Area of entire circle = pi*r^2=3.14 * 18^2 = 1017.26
1/4 of Area = 1/4 * 10.17.26 = 254.34 sq in
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(e)Net Area = Area 1/4 circle - 2* Area each Rhombus
A= 254.34 -2(70) = 114.24 sq in
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