Question 206091: The sum of the ages of a couple is 60. In eight years, husband's age will be five years less than two times the wife's age seven years ago. Find their present ages.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The sum of the ages of a couple is 60. In eight years, husband's age will be five years less than two times the wife's age seven years ago. Find their present ages.
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NOW DATA:
d + m = 60
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8 yrs. from now DATA:
(d+8)=2(m-7)-5
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Simplify the 2nd equation:
d - 2m = -14-8-5
d-2m = -27
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You now have the system:
d+m = 60
d-2m=-27
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Subtract the 2nd from the 1st to solve for "m"
3m = 87
m = 29 yrs old (the spouse's age NOW)
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Since d+m = 60 , d = 31 yrs old (the husband's age NOW)
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Cheers,
Stan H,
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