Question 206069: Hi, Im having problems trying to solve these complex fractions. its a extraneous solution. Can you help please.
ab + b^2/4ab^5
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a+b/6a^2b^4
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! { (ab+b^2) / (4ab^5)} / {(a+b)/(6a^2b^4)}
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invert and multiply
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{ (ab+b^2)/(4ab^5)} * {(6a^2b^4)/(a+b)}
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factor and simplify by cancelling like terms
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{ (b)(a+b) / (4 a b^5)} * { (6 a^2 b^4)/ (a+b) }
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{ 3 a /2 }
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(3/2) a = 1.5a
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check,,,Let a = 2,,,,b=1,,,,both original and answer = 3,,,,ok
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