SOLUTION: x^2 - 3x^1/2 - 10 = 0

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: x^2 - 3x^1/2 - 10 = 0      Log On


   



Question 206019This question is from textbook Intermediate Algebra
: x^2 - 3x^1/2 - 10 = 0 This question is from textbook Intermediate Algebra

Answer by mickclns(59) About Me  (Show Source):
You can put this solution on YOUR website!
+x%5E2+-+%283x%5E1%29+%2F+2+-+10+=+0+ notation housekeeping
+x%5E2+-+%283%2F2%29x+-+10+=+0+ multiply both sides by 2 to get rid of the fraction
+2x%5E2+-+3x+-+20+=+0+
There are various ways of factoring a quadratic (if it factors, which this does, because b%5E2-4%2Aa%2Ac+=+9+%2B+160+=+169+ is a perfect square). I like this way:
+2x%5E2+-+3x+-+20+=+0+ First multiply the coefficient of the +x%5E2+ term, 2, by the constant term, -20, to get -40. Now you want to find two numbers that multiply to this number, -40, and that add to the coefficient of x, in this case -3. The two numbers are -8 and 5.
Now you put those two numbers into the blanks in +2x%5E2+%2B+_x++%2B+_x+-+20+ (and it doesn't matter which number in which blank):
 
Case 1: +2x%5E2+%2B+%28-8%29x++%2B+%285%29x+-+20+. Now factor out whatever you can out of the first two terms and factor out whatever you can out of the last two terms:
2x%28x+-+4%29+%2B+5%28x+-+4%29. Notice both terms have a factor of x-4 which you can factor out:
%282x+%2B+5%29+%28x-4%29.
 
Case 2: +2x%5E2+%2B+%285%29x++%2B+%28-8%29x+-+20+. Now factor out whatever you can out of the first two terms and factor out whatever you can out of the last two terms:
x%282x+%2B5%29+%2B+-4%282x+%2B+5%29. Again, both terms have a factor, 2x + 5 this time, which you can factor out:
%28x-4%29+%282x+%2B+5%29.
 
In both cases the factors are the same except in opposite order, which makes not a whit of difference.
It is a good idea to multiply out (FOIL) to make sure you have factored correctly
 
Now we use the zero product property which says that if a product of a bunch of numbers is 0 then one of the numbers must be 0, which is what allows us to set each of the factors to 0.
%28x-4%29+%282x+%2B+5%29+=+0 --> x-4+=+0 or 2x%2B5+=+0, so x+=+4 or x+=+-5%2F2.
Now it's a good idea to check your answers to make sure they work, by plugging them in (one at a time) for x in the ORIGINAL equation (I will do one, you can do the other):
+%28-5%2F2%29%5E2+-+%283%28-5%2F2%29%5E1%29+%2F+2+-+10+=+0+ ?
+25%2F4+%2B+15%2F4+-+10+=+0?
40%2F4+-+10+=+0?
0+=+0 Yes!