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Question 205923: Q(x)=5x2-6x+3; find Q(1/2)
Determine the domain of the function.
P(x)=x2-2x-10
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5x2+10x
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Q(x)=5x2-6x+3; find Q(1/2)
Q(1/2) = 5(1/2)^2 - 6(1/2) + 3
= (5/4) - 3 + 3
= 5/4
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Determine the domain of the function.
P(x)=x^2-2x-10
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5x^2+10x
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Factor to get:
P(x) = [x^2-2x-10)/[5x(x+2)]
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Since the denominator cannot be zero,
x cannot be 0 and x cannot be -2
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Domain: All Real Numbers except x = -2 and x = 0
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Cheers,
Stan H.
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