Question 205848: Solve the problem.
Give the equation of the line that is perpendicular to the line y = -3x + 7 and passes through point (0, -6).
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! Give the equation of the line that is perpendicular to the line y = -3x + 7 and passes through point (0, -6).
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The slope of:
y = -3x + 7
is -3
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A line perpendicular, then, must be the negative reciprocal or 1/3.
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Therefore, our new line:
m = 1/3
and crossing:
(0, -6)
.
Plug that into the "point slope" form:
y - y1 = m(x-x1)
y - (-6) = (1/3)(x-0)
y + 6 = (1/3)(x)
y = (1/3)(x) - 6 (this is what they're looking for)
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