Question 205662This question is from textbook Algebra I:An Incremental Development
: PLEASE help me with this subscripter variable:
3N^N+3N^Q=9
2N^N=10-6N^Q
This question is from textbook Algebra I:An Incremental Development
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! (1) 3n^n +3n^q =9,,,,n^n = (9-3n^q)/3 = 3-n^q
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(2) 2n^n +6n^q =10
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subst (1) into (2)
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2(3-n^q) +6n^q =10
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6-2n^q +6n^q =10
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4n^q=4
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n^q=1,,,,,,therefore q=0,,,,anything raised to 0 =1,,,
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subst into (1),,,,3n^n +3n^0 =9
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n^n +n^0 =3
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n^n +1 =3
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n^n =2
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n= 1.56
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check(1) 3*1.56^1.56 +3*1.56^0 =9
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6 +3=9,,,,,ok
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(2) 2*1.56^1.56 = 10 - 6*1.56^0
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4= 10 -6 =4,,,,ok
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