SOLUTION: Separate 45 into two parts such that 5 times the smaller is 6 less than twice the larger

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Question 20553: Separate 45 into two parts such that 5 times the smaller is 6 less than twice the larger
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the smaller part of 45.
5x+=+2%2845-x%29+-+6 Simplify and solve for x.
5x+=+90+-+2x+-+6 Add 2x to both sides of the equation.
7x+=+84 Divide both sides by 7.
x+=+12
The smaller part is 12 and the larger part is 45-12 = 33.