SOLUTION: The length of the Rhombus is 52cm. One of its diagonal is 48 cm. Find the length of the other diagonal and the area of the Rhombus.

Algebra ->  Pythagorean-theorem -> SOLUTION: The length of the Rhombus is 52cm. One of its diagonal is 48 cm. Find the length of the other diagonal and the area of the Rhombus.      Log On


   

Question 205492: The length of the Rhombus is 52cm. One of its diagonal is 48 cm. Find the length of the other diagonal and the area of the Rhombus.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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The length of the Rhombus is 52cm. One of its diagonal is 48 cm. Find the length of the other diagonal and the area of the Rhombus.
:
you can see that the two diagonals form 4 identical right triangles
The hypotenuse = 52 cm (one side)
One leg = half the short diagonal which is 48cm = 24 cm
The other leg = half the longer diagonal (x)
:
Find the other leg (x)
x = sqrt%2852%5E2+-+24%5E2%29
x = 46.13
:
2 * 46.13 = 92.26 cm is the longer diagonal
:
The area will be the total area of the 4 right triangles
:
2 * (46.13 * 24) = 2214.24 sq/cm; (area of the 4 triangles)