SOLUTION: What is the value of X in this logarithm? log{{{6}}}(2x-5) + 1 = log{{{6}}}(7x+10) Please walk me through this equation.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: What is the value of X in this logarithm? log{{{6}}}(2x-5) + 1 = log{{{6}}}(7x+10) Please walk me through this equation.      Log On


   

Question 20543: What is the value of X in this logarithm? log6(2x-5) + 1 = log6(7x+10) Please walk me through this equation.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Recall:
If log6a = log6b, then a = b
log6(2x-5) = log6(7x+10)
(2x-5) = (7x+10) Subtract 2x from both sides.
-5 = 5x+10 Subtract 10 to bothsides.
-15 = 5x Divide both sides by 5.
x = -3
Check:
log6(2(-3)-5) = log6(7(-3)+10)
log6(-11) = log6(-21+10)
log6(-11) = log6(-11)