SOLUTION: A designer created a garden from 2 concentric circles whose equations are as follows:
(x+2)^2+(y-6)^2=16 and
(x+2)^2+(y-6)^2=81
The area between the circles will be covered wit
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-> SOLUTION: A designer created a garden from 2 concentric circles whose equations are as follows:
(x+2)^2+(y-6)^2=16 and
(x+2)^2+(y-6)^2=81
The area between the circles will be covered wit
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Question 205404: A designer created a garden from 2 concentric circles whose equations are as follows:
(x+2)^2+(y-6)^2=16 and
(x+2)^2+(y-6)^2=81
The area between the circles will be covered with grass. What is the area of that section? Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! The plan is to find the area of each circle and then subtract the smaller area from the larger area to get the area of the annulus.
The two circles are defined by: and...
Comparing these with the general form of the equation of a circle with center at (h, k) and radius, r: you can immediately read off the square of the radius of each circle as and respectively.
The area of each circle is given by: and... so you have... and... Subtracting you get: =sq.units. (Approx.)
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