Question 205332: find 3 consecutive even integers such that five times the second equals twice the sum of the first and third Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find 3 consecutive even integers such that five times the second equals twice the sum of the first and third
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1st: 2x
2nd: 2x+2
3rd: 2x+5
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Equation:
5(2x+2) = 2(2x + 2x+5)
10x + 10 = 2(5x+10)
10x + 10 = 10x + 20
0 = 10
That is a contradiction.
There are no consecutive even integers that meet the requirement.
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Cheers,
Stan H.