Question 20508: The length of a rectangle playing field is 5ft. less than twice its width. If the perimeter of the playing field is 230 ft, find the length and width of the field.
Answer by suresh(20) (Show Source):
You can put this solution on YOUR website! Perimeter of the rectangle is = 2 ( l + b ) ,where l is the length and b is the breath of the rectangle.
Let b be the width of the rectangle.
Given, l = 2 b - 5.
Also perimeter = 230 ft.
Therefore, 2 (2b - 5 + b ) = 230
2 ( 3b - 5) = 230
6b-10=230
6b=240
b=40.
l=2(40)-5=80-5=75.
Hence, l = 75 and b= 40
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