Question 204857This question is from textbook Introductory Algebra
: Find the equation of the line that contains the point (1,0) and is perpendicular to 2x+y=-4.
First, find the slope:
2x+y=-4
2x-2x+y=-2x-4
y=-2x-4
Slope is -2.
The slope of the perpendicular line would be the reciprocal of -2 with the sign changed. Reciprocal of -2/1 is -1/2 and changing the sign gives 1/2.
Slope is 1/2.
I know we then need to find the y intercept and find the value of b; however, I cannot figure out how to get to this point. Please assist in helping me from here to solve this problem. Once I see the work, I then understand how to do it and can work backwards to do them in the future.
Thanks for the help! BTW, this is due Sunday, so I need it before then if possible. Thanks again.
This question is from textbook Introductory Algebra
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find the equation of the line that contains the point (1,0) and is perpendicular to 2x+y=-4.
First, find the slope:
2x+y=-4
2x-2x+y=-2x-4
y=-2x-4
Slope is -2.
The slope of the perpendicular line would be the reciprocal of -2 with the sign changed. Reciprocal of -2/1 is -1/2 and changing the sign gives 1/2.
Slope is 1/2.
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The slope is 1/2, as you determined.
Then use:
y-y1 = m*(x-x1) where (x1,y1) is the point (1,0)
y-0 = (1/2)*(x-1)
y = (1/2)x - 1/2 slope-intercept form
x - 2y = 1 standard form
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