SOLUTION: A candy shop mixes nuts worth $1.10 per pound with another variety worth $0.80 per pound in order to make 42 lb of a mixture worth $0.90 per pound. How many pounds of each kind of

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A candy shop mixes nuts worth $1.10 per pound with another variety worth $0.80 per pound in order to make 42 lb of a mixture worth $0.90 per pound. How many pounds of each kind of       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 204753: A candy shop mixes nuts worth $1.10 per pound with another variety worth $0.80 per pound in order to make 42 lb of a mixture worth $0.90 per pound. How many pounds of each kind of nut should be used?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
A candy shop mixes nuts worth $1.10 per pound with another variety worth $0.80 per pound in order to make 42 lb of a mixture worth $0.90 per pound. How many pounds of each kind of nut should be used?
.
Let x = amount of $1.10 per pound nuts used
then
42-x = amount of $0.80 per pound nuts uses
.
1.10x + .80(42-x) = .90(42)
1.10x + 33.6 - .80x = 37.8
.30x + 33.6 = 37.8
.30x = 4.2
x = 14 pounds ($1.10 per pound nuts)
.
$0.80 nuts:
42-x = 42-14 = 28 pounds ($0.80 per pound nuts)