SOLUTION: Please help! Find all numbers such that the sum of the number and 10 is less than 3 times the number. So do you sent the problem up like: x + 10 = 3x??

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Please help! Find all numbers such that the sum of the number and 10 is less than 3 times the number. So do you sent the problem up like: x + 10 = 3x??       Log On


   



Question 204737: Please help!
Find all numbers such that the sum of the number and 10 is less than 3 times the number.
So do you sent the problem up like:
x + 10 = 3x??

Found 2 solutions by Earlsdon, stanbon:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You were close! But notice that the probem says "...the sum of the number and 10 "is less than" 3 times the number, so this can be expressed as the inequality:
highlight%28x%2B10+%3C+3x%29 where x is the number.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find all numbers such that the sum of the number and 10 is less than 3 times the number.
So do you set the problem up like:
x + 10 = 3x ??
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Yes, because you want to solve the INEQUALITY.
In order to do that you need to determine the boundary of the INEQUALITY
which is the solution to the EQUALITY.
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So, x+10 = 3x
2x = 10
x = 5 is the boundary.
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Now you check a value on each side of the boundary to see where
the solutions for the INEQUALITY lie.
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Check x = 10 in the INEQUALITY you get 10 + 10 > 30
That is false so there are no solutions to the right of x=5.
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Checking x = 0 in the INEQUALITY you get 0+10>3*0
That is true so all the solutions are to the left of x = 5.
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Solution: x < 5
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Cheers,
Stan H.