SOLUTION: find two consecutive odd integers such that twice the lager is 17 more than the smaller

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Question 204692This question is from textbook Algebra 1
: find two consecutive odd integers such that twice the lager is 17 more than the smaller This question is from textbook Algebra 1

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Let x & x+2 be the 2 integers.
2(x+2)=x+17
2x+4=x+17
2x-x=17-4
x=13 ans. for the smaller integer.
13+2=15 ans. for the larger integer.
Proof:
2*15=13+17
30=30