SOLUTION: Hi all, I was hoping someone could show me how to do the following: I need to express [16(a^2*b^4)^(-1/2)] / [b-3] as a single fraction involving no negative powers. If someone

Algebra ->  Equations -> SOLUTION: Hi all, I was hoping someone could show me how to do the following: I need to express [16(a^2*b^4)^(-1/2)] / [b-3] as a single fraction involving no negative powers. If someone      Log On


   

Question 204657: Hi all, I was hoping someone could show me how to do the following: I need to express [16(a^2*b^4)^(-1/2)] / [b-3] as a single fraction involving no negative powers. If someone could show me how to do this with full working and explanations, that would be very helpful.
Thnaks -Nick.
Found 2 solutions by alicealc, Alan3354:
Answer by alicealc(293) About Me  (Show Source):
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
need to express [16(a^2*b^4)^(-1/2)] / [b-3] as a single fraction involving no negative powers.
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[16(a^2*b^4)^(-1/2)] = 1/[16(a^2*b^4)^(1/2)]
= 16/ab^2
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was b-3 supposed to be b^(-3) ?
If so:
1/b^(-3) = b^3
--> 16b/a