Question 204367: Find all real numbers that are not in the domain of the following function:
f(x)=x^2+4x+1/2x^2+x-3
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! f(x) = (x^2 +4x +1) / (2x^2 +x-3)
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factor
f(x) = (x+3.732)(x+.268) / (2x+3) (x-1)
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ps. used quadratic formula for numerator, but it doesn't come into play
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To be out of the Domain, the function can be (1) undefined, by having zero in denominator,,or(2) complex,,sqrt of negative number
in this case if (2x+3) =0,, x=-3/2,,,,or (x-1)=0,,x=1,,,, function is undefined
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Therefore Domain is ALL REAL NUMBERS,,except x=-3/2 and x=1
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